Home Vacancy BPSC TRE-2 Lecturer Shikshak Bharti: Last date for registration for 1-22 lakh...

BPSC TRE-2 Lecturer Shikshak Bharti: Last date for registration for 1-22 lakh teacher recruitment apply today 25th November


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BPSC TRE-2: Today is the last date for registration in the second phase teacher recruitment examination (BPSC TRE-2) of Bihar Public Service Commission. Candidates willing to apply for Bihar 1.22 lakh teacher recruitment 2023 can complete their registration by the evening of 14th November. Candidates registering will have time till 25 November 2023 to fill the online application form. That is, only the candidates who have registered till this evening will be able to fill the form on the Commission’s website www.bpsc.bih.nic.in till the last date of application. The Commission has clearly said that the last date of application will not be extended. Apart from this, like last time, B.Ed and CTET appearing candidates will not be given a chance to apply in TRE-2.

BPSC Chairman Atul Prasad had announced the new teacher recruitment 2023 on 4 November 2023. The Commission Chairman had told that registration for new Bihar teacher recruitment can be done from November 5 to November 14 and applications can be made from November 10 to November 25, 2023. Let us tell you that in this recruitment of BPSC, advertisement was issued for 70 thousand posts in which more than 50 thousand 600 vacancies have been added. That means now eligible candidates will be selected on a total of 1.22 lakh posts.

Information about important changes in the examination for new teacher recruitment was also given. Commission Chairman said that keeping in mind the problems faced by the candidates in the process of TI-1, some changes have been made in some teacher recruitment examinations. The main change in the Bihar Teacher Recruitment Examination is that now the examination will be held on one day instead of two days. Also, instead of two papers, there will now be only one paper. Also, now there will be no minus marking in the teacher recruitment examination.

New rule for tie breaker:
The total marks for the merit list by combining Part 2 and Part 3 of the paper will be 120 marks. If there is a tie breaker result then the eligible candidate will be selected on the basis of marks of Part-3. If there is a tie breaker in Part 3 also, then the one who gets more marks in Language, which is of qualifying nature, will be considered qualified. If there are equal marks in language subject then name and date of birth will be given preference.